where rn[ where The derivative with respect to a parameter, and using Eq. (2) we obtain which is the HellmannFeynman expression with an additional nodal term. While h
th pocket, 
, is zero on the surface of the pocket. For simplicity we consider only ground-state wave functions which satisfy the tiling property7,8 that all nodal pockets are equivalent and related by the permutation symmetry. The pocket wave function is zero outside the pocket and has a discontinuous derivative at the surface of the pocket and, therefore, satisfies8 
] is the surface of pocket
. The delta function term, which was neglected by Schautz and Flad,1 arises from the action of the kinetic-energy operator on the discontinuity in the derivative of the wave function at the pocket surface. Operating on this equation with the antisymmetrizing operator, Â, gives
= Â
is the antisymmetric DMC wave function and rn[
] is the nodal surface of
. The nodal surface is fixed by the choice of the trial wave function,
T. The DMC energy may then be calculated from
T is exact then
has no gradient discontinuities on the nodal surface and 
0 = E0
0, where
0 and E0 are the exact wave function and energy, but if the nodal surface is inexact then h[
] is nonzero and normally of order
0. On substituting Eq. (2) into Eq. (3) we find that the nodal term, h
, does not contribute to the energy because
T is zero on the nodal surface. However, the nodal term can contribute to derivatives of ED. A simple way to see this is to note that the DMC energy can also be evaluated as the expectation value with the fixed-node DMC wave function
, is
is determined by the nodes of
(or equivalently those of
T), ![[partial-derivative]](/stockgif2/part.gif)
/![[partial-derivative]](/stockgif2/part.gif)
depends on how we choose the nodes to vary with
. We, therefore, expect the nodal term in Eq. (6) to be nonzero in general. If we choose the nodes to be independent of
then ![[partial-derivative]](/stockgif2/part.gif)
/![[partial-derivative]](/stockgif2/part.gif)
= 0 on the nodal surface and the contribution from the nodal term is zero. In this case the HellmannFeynman theorem holds, as correctly stated by Schautz and Flad.1 However, if the nodes of the trial wave function vary with
then the nodal term will normally be nonzero and the HellmannFeynman expression does not give the exact derivative of the DMC energy of Eqs. (3) and (4), in contradiction to Schautz and Flad.1
if the nodes are independent of
, but this does not hold in general if the nodal surface depends on
.
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